~2 min read • Updated Mar 9, 2026
Introduction to Derivatives of Inverse Trigonometric Functions
Inverse trigonometric functions such as arcsin, arccos, and arctan appear frequently in geometric, physical, and analytical problems.
To analyze these functions precisely, understanding their derivatives is essential.
1. Derivatives of Basic Inverse Trigonometric Functions
(arcsin(x))' = 1 / √(1 - x²)(arccos(x))' = -1 / √(1 - x²)(arctan(x))' = 1 / (1 + x²)(arccot(x))' = -1 / (1 + x²)(arcsec(x))' = 1 / (|x| √(x² - 1))(arccsc(x))' = -1 / (|x| √(x² - 1))
Example:
(arcsin(3x))' = 3 / √(1 - 9x²)2. Derivatives of Composite Inverse Trigonometric Functions
For functions such as arctan(ax + b) or arcsin(x²), the chain rule is applied.
Example:
(arctan(2x + 1))' = 2 / (1 + (2x + 1)²)
(arcsin(x²))' = (2x) / √(1 - x⁴)3. Idea Behind Deriving These Formulas
For example, to derive the derivative of arcsin(x), set:
y = arcsin(x) ⇒ sin(y) = xDifferentiating implicitly gives:
cos(y) y' = 1
Since:
cos(y) = √(1 - sin²(y)) = √(1 - x²)We obtain:
y' = 1 / √(1 - x²)4. Applications of Inverse Trigonometric Derivatives
- Solving differential equations
- Analyzing rotational and angular motion
- Evaluating complex integrals
- Modeling nonlinear physical phenomena
5. Combined Examples
Example 1:
(x arccos(x))' = arccos(x) - x / √(1 - x²)Example 2:
(arctan(1/x))' = -1 / (x² + 1)Conclusion
Derivatives of inverse trigonometric functions form an important part of differential calculus.
Knowing these formulas allows us to solve more advanced problems in geometry, physics, and mathematical analysis.
These derivatives are powerful tools for understanding the behavior of nonlinear functions.
Written & researched by Dr. Shahin Siami