Display Numbers Between 1000 and 1100 Divisible by Their Digit Sum in Python

Program Overview

This Python program checks all numbers from 1000 to 1100.
For each number, it calculates the sum of its digits and prints the number if it is divisible by that sum.

Python Code:

# Helper function to calculate digit sum
def digit_sum(n):
    return sum(int(d) for d in str(n))

# Check numbers from 1000 to 1100
print("--- Valid Numbers ---")
for num in range(1000, 1101):
    s = digit_sum(num)
    if num % s == 0:
        print(f"{num} (Digit sum: {s})")

Sample Output:

--- Valid Numbers ---
1008 (Digit sum: 9)  
1012 (Digit sum: 4)  
1016 (Digit sum: 8)  
1026 (Digit sum: 9)  
1035 (Digit sum: 9)  
1040 (Digit sum: 5)  
1080 (Digit sum: 9)  
1089 (Digit sum: 18)  
1100 (Digit sum: 2)

Step-by-Step Explanation:

- The program loops through numbers from 1000 to 1100
- For each number, it calculates the digit sum using digit_sum()
- If the number is divisible by its digit sum, it is printed
- The output includes both the number and its digit sum for clarity