This Python program reads an integer n and computes the result of the following series:
∑ [log(k^(k-1) / (k^k - 1))] for k from 2 to n
It uses math.log for natural logarithm calculations.
import math
def compute_log_series(n: int) -> float:
total = 0.0
for k in range(2, n + 1):
numerator = k ** (k - 1)
denominator = k ** k - 1
term = math.log(numerator / denominator)
total += term
return total
# Read input from user
n = int(input("Enter value for n: "))
result = compute_log_series(n)
print(f"Series result is: {result:.6f}")
Series result is: -1.191274